Question

Solve this please \leqslant x + 5" alt="2x + 3 \leqslant x + 5" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

x ≤ 2

Step-by-step explanation:

Isolate the variable, x. Note the ≤ sign, treat it like an equal sign, what you do to one side, you do to the other.

First, subtract 3 and x from both sides:

2x (-x) + 3 (-3) ≤ x (-x) + 5 (-3)

2x - x ≤ 5 - 3

Simplify:

2x - x ≤ 5 - 3

x ≤ 2

x ≤ 2 is your answer.

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