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stepladder [879]
3 years ago
9

Will give brainliest and 25 points!!! Pls help me out!!!

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

(-3, 1.5)

Step-by-step explanation:

-8 +5 = -3

2 + -2 = 1.5

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There are 95 students at an
Morgarella [4.7K]
I believe 14.
95 divided by 7 is 13.57 so Round up to 14.
7 0
3 years ago
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Help tried my best but couldn’t get it
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Answer:

1. 115

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6 0
3 years ago
Jeannine runs for 45 minutes every day for exercise. it takes her 8 minutes to run a mile, and she spends 5 minutes stretching h
ki77a [65]
8x5<45         So the fewest of miles she could run is 1, 2, 3, or 4 miles
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6 0
4 years ago
Can someone check on this problem if I did it right this problem is about law of cosines just look at #1
lora16 [44]

Answer:

x = 5.57

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8 0
4 years ago
(1 point) Some airlines have restrictions on the size of items of luggage that passengers are allowed to take with them. Suppose
Kamila [148]
Here L = W, but H can be different.
 
The sum L+H+W  must be less than or equal to 192 cm.  

We can solve L + H + W = 192 for H:  H = 192 - W - L.  Remembering that W = L,   the formula for H becomes 192 - 2W.

The formula for volume would be V = L*W*H.

This becomes V = W*W*H, or  V = W^2*(192-2W)

Multiplying this out:  V = w^2*192 - 2W^3

Two ways of determining W:

1) graph V = 192W^2 - 2W^3 and determine the value of W at which V is at a max with the constraint W + L + H is equal to or smaller than 192.

2) Differentiate V with respect to W and set the result equal to zero:

384W - 6W^2 = 0.  Solving for W:  W(384 - 6W) = 0.

W = 0 is trivial, so just solve 384 - 6W = 0 for W:  6W = 384, and W = 64.

The width is 64 cm, the length is 64 cm also, and the height is (192-2W) cm, or 64 cm.

These dimensions produce the max volume.
4 0
3 years ago
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