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ratelena [41]
2 years ago
14

What is the value of x in the proportion x + 1 / x+3 = 15/ 21 a.4 b.1/3 c.1/4 d.3

Mathematics
2 answers:
vladimir2022 [97]2 years ago
8 0
×+1/×+3=15/21
×+1=15(×+3)/21
×+1=15×+45/21
21(×+1)=15×+45
21×+21=15×+45
21×-15×=45-21
6×=24
×=4
lesantik [10]2 years ago
3 0
<span>What is the value of x in the proportion x + 1 / x+3 = 15/ 21
a.4
b.1/3
c.1/4
d.3</span>
the answer is            
a.) 4
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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy
lisov135 [29]

Answer:

300\; \rm lb.

Step-by-step explanation:

Let x represent the mass (in pounds) of that 15\% copper alloy required, such that the final mixture would contain 25.5\% copper by mass.

Consider: if x pounds of that 15\% copper alloy is mixed with 700 pounds that 30\% copper alloy, what would be the mass of copper in the mixture?

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Therefore, the mixture would contain (210 + 0.15\, x) \; \rm lb of copper.

The mass of that mixture would be (700 + x)\; \rm lb. The mass fraction of copper in that mixture would be:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%.

This ratio is supposed to be equal to 25.5\%. These two pieces of equations combine to give an equation about x:

\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%.

\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255.

Simplify and solve for x:

210 + 0.15\, x= 0.255\, (700 + x).

(0.255 - 0.15)\, x= 210 - 0.255 \times 700.

\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300.

Therefore, 300\; \rm lb of that 15\% alloy would be required.

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
MrRissso [65]

Answer:

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-2(3x-5)=16

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