Looking at the graph closely we can see that the heart rate increases from 0 to 6 min then became steady from 6 to 25 min then finally decreases from 25 to 30 min. Therefore the correct answer is:
“The heart rate increases for 6 minutes, remains constant for 19 minutes, and then gradually decreases for 5 minutes.”
In real life cardiac exercises, we can interpret that the period from 0 to 6 min is the period where the person is still warming up thus leading to an increase in heart rate. At 6 min, the person is fully warmed up hence reaching a stable heart rate. Then at 25 min, the person starts cooling down which means that the exercise is ending soon.
Answer:
All fractions except 2/3 lol
Step-by-step explanation:
1.32 that would be the answer because you would have to times it
Answer:
V = 125.6 in³
Step-by-step explanation:
let V be volume, h the height and r the radius, then the equation relating the quantities is
V = khr² ← k is the constant of variation
To find k use the condition V = 402.12, h = 8, r = 4
402.12 = k × 8 × 4² = 128k ( divide both sides by 128 )
3.14 = k [ note 3.14 is π )
V = 3.14hr² ← equation of variation [ V = πr²h ]
Given r = 2 and h = 10, then
V = 3.14 × 10 × 2² = 3.14 × 40 = 125.6
