Answer:
7
Step-by-step explanation:
Use secant-tangent product theorem.
1. Set up the equation
(x-3)(x-3+5) = (x-1)²
2. Solve
(x-3)(x+2) = (x²-2x+1)
(x²-x-6) = (x²-2x+1)
3. Solve for x
Subtract x² from both sides
-x-6 = -2x+1
Add 2x and 6 to both sides
x = 7
Step-by-step explanation:
I think the fig.. will helps you a lot...
Side of the original square. x2 x<span>. Square </span>has all<span> sides the same </span>length x<span> ... </span>2<span>. Our Solution. Example 3. The </span>length<span> of a </span>rectangle<span> is </span>4<span> ft greater than the </span>width<span>. If each </span>dimension<span> is ... (x+ 3)(x+ 7) =</span>x<span>(x+ </span>4<span>) +33 Set up equation, </span>length times width<span> is area .... </span>5<span>) </span>6 x 10<span>. </span>6<span>) 20 ft </span>x<span> 35 ft. 7) </span>6<span>” </span>x 6<span>”. </span>8<span>) </span>6<span> yd </span>x<span> 7 yd. </span>9<span>) </span>4<span> ft </span>x<span> 12 ft. </span>10<span>) 1.54 in.</span>
