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aivan3 [116]
3 years ago
14

What are the domain and range of f(x)= (1/5)^x

Mathematics
2 answers:
Aneli [31]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

nevsk [136]3 years ago
3 0
The answer for the question shown above is the second one, which is: The domain is all real numbers. The range is all real numbers greater than zero.

 The explanation is shown below:

 You have the following function given in the problem above f(x)= (1/5)^x. As you can see, it is a exponential function. By definition, the domain of the exponential functions is all  the real numbers anf their range is all real numbers greater that zero.
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PRECALCULUS please help​
sergejj [24]

Answer:

<h2>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h2>

Step-by-step explanation:

f(x) =  \frac{2x + 6}{3x}  \\  \\ g(x) =  \frac{ \sqrt{x}  - 8}{3x}

To find ( f - g)(x) , subtract g(x) from f(x)

That's

( f - g)(x) =  \frac{2x + 6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}

Since they have a common denominator that's 3x we can subtract them directly

That's

\frac{2x  +  6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}    =  \frac{2x  + 6 - ( \sqrt{x} - 8) }{3x}  \\  =  \frac{2x + 6 -  \sqrt{x} + 8 }{3x}  \\  =  \frac{2x -  \sqrt{x} + 6 + 8 }{3x}

We have the final answer as

<h3>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h3>

Hope this helps you

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