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Vsevolod [243]
3 years ago
8

Can anyone explain the basics of solving systems to linear equations?

Mathematics
2 answers:
masya89 [10]3 years ago
4 0

Answer:

A basics of solving systems to linear equations is somthing when you use it you do olve one of the equations for one of the variables. Let's solve the first equation for y: ...

Step 2: Substitute that equation into the other equation, and solve for x. ...

Step 3: Substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

Step-by-step explanation:

Len [333]3 years ago
3 0

Answer:

A system of linear equations is just a set of two or more linear equations. In two variables (x and y) , the graph of a system of two equations is a pair of lines in the plane. ... The lines intersect at infinitely many points.

Step-by-step explanation:

i hope this helped

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Segment EF is the midsegment of trapezoid ABCD. Find the length of segment EF if segment AB is 20 and segment CD is 12.
Vika [28.1K]

Midsegment = 1/2(base1 + base2)

EF = 1/2(AB + CD)

EF = 1/2(20 + 12)

EF = 1/2(32)

EF = 16

Answer

EF = 16

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3 years ago
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How much was deposited in the account if the amount in the
Mrac [35]

Answer:

$98.33 was deposited in the account

Step-by-step explanation:

simple interest formula = (PRT)/100 ...where p is money, r is rate, t is time

using formula  $17.70 = (P *  3% * 6)/100

                         P = 1770/18

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How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled
spayn [35]

The volume of oblique cone =\frac{1}{3} \pi r^{2} h

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = \frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)

= \frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )=4*(\frac{1}{3} \pi r^{2} h )

It means the volume becomes 4 times

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3 years ago
What is the formula for the area A of a circle in terms of the radius r?​
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Answer:

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Step-by-step explanation:

5 0
2 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
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