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ohaa [14]
3 years ago
5

1 point

Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

 b

Step-by-step explanation:

done it

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7-5x+1 please answer i need this NOW!!!!!!!!!!!!!!!!!!!!!
Alisiya [41]

Answer:x=8/5 or 1.6

​​  

Step-by-step explanation:

5 0
3 years ago
A line passes through (4, 5) and (8, 9). Which equation best represents the line?
xxTIMURxx [149]

Answer:

that is the equation of the line, its slope is 1 and the y-intercept is 1 y = x + 1

Step-by-step explanation:

we can calculate the slope of this line passing through (4,5) and (8,9) like this:

m = (y2 - y1)/(x2 - x1)

m = (9 - 5)/(8 - 4)

m = 4/4

m = 1

so the slope is 1, and now we can use the equation of one point and the slope to write the line's equation:

y - y1 = m(x - x1)

y - 5 = 1*(x - 4)

y - 5 = x - 4

y = x + 1

that is the equation of the line, its slope is 1 and the y-intercept is 1



7 0
3 years ago
A school wants to buy a chalkboard that measures 3 feet by 4 feet the chalkboard cost $6.14 per square foot. How much will the c
ElenaW [278]

Answer:

$49.12

Step-by-step explanation:

8 0
3 years ago
student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
Help me with this please
photoshop1234 [79]

Answer:

ANSWER:D

Step-by-step explanation:

Sana maka help

5 0
2 years ago
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