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2 years ago

Will give BRAINLYIST answer Which transformations are used to create triangle a ABC

Mathematics

2 answers:

natulia [17]2 years ago

6 0

Answer:

A, dilation by a scale factor of 2 and a reflection across the y-axis

Step-by-step explanation:

KonstantinChe [14]2 years ago

5 0

Answer:

A dilation of 2 and a reflection across the y-axis.

Step-by-step explanation:

Dilating it by two, makes it bigger. Which eliminates two. Then, if you rotated 90 degrees clockwise, it wouldn't end up in the correct placement. But, If you reflected it across the y-axis, it would end up in the correct place.

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Write the set by listing its elements.

IceJOKER [234]

Step-by-step explanation:

set o= o

set t= t

those are the set of letters used to form the set

7 0

3 years ago

Helppp!!!! please!!!

KatRina [158]

Answer:

Option B is the correct answer

Step-by-step explanation:

Center of the circle lie on point (-1, - 3) = (h, k)

$\implies \: h = - 1 \: \: k = - 3 \\radius \: r \: = 2 \\ equation \: of \: circle \: in \: standard \: form \: \\ is \: given \: as : \\ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\ {(x + 1)}^{2} + {(y + 3)}^{2} = {2}^{2} \\ \purple{ \boxed{ \bold{ {(x + 1)}^{2} + {(y + 3)}^{2} = 4}}}$

8 0

3 years ago

Find the output, k, when the input, t, is -7<br><br> K = 10t - 19 <br><br> K= ?

Katarina [22]

Answer:

k= -89

Step-by-step explanation:

k = 10t - 19 and t = -7

k=10 (-7) - 19

k= -70 - 19

k= -89

3 0

3 years ago

Find the area of a triangle whose base is x^2+2x+4 and whose height is 2x^2x +2x+6

kkurt [141]

The base of the triangle is x² + 2x + 4
The height of the triangle is 2x² + 2x + 6
The area of the triangle is
A = (1/2) b h
Substituting
A = (1/2)(x² + 2x + 4)(2x² + 2x + 6)
Which can be expanded or factored

6 0

3 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago