Answer:
Choice D. 15.2%
Step-by-step explanation:
We have a normal...
mean u = 48
standard deviation s = 2
We want P(43 < X < 46)
We standardize.
Consider P(43 < X) = P( (43 - 48)/2 < Z) = P(-2.5 < Z)
P( X < 46) = P( Z < (46 - 48)/2 ) = P(Z < -1)
We want P( -2.5 < Z < -1)
Look at Z-scores.
P( Z < -2.5) = 0.0062
P(Z < -1) = 0.1587
so P(-2.5 < Z < -1) = P(Z < -1) - P(Z < -2.5) = 0.1587 - 0.0062 = 0.1525 = 15.2%
about
Answer:
Rock travels about 8.2x²meters higher on the moon than on the Earth.
Step-by-step explanation:
Expression showing the height of a rock thrown into the air at Earth is,
f(x) = -9.8x² + 10x + 1.5
Similarly, expression showing the height of rock thrown on the moon is,
g(x) = -1.6x² + 10x + 1.5
Difference in the height of the rock thrown on moon = g(x) - f(x)
= (-1.6x² + 10x + 1.5) - ( -9.8x² + 10x + 1.5)
= -1.6x² + 9.8x² + 10x - 10x + 1.5 - 1.5
= 8.2x²
Therefore, rock travels about 8.2x²meters higher on the moon than on the Earth.
Compute the derivative of
at
- this will be the tangent vector - then normalize it by dividing it by its magnitude to get the unit tangent vector
.



<h2>
Answer:</h2>

and,

<h2>
Step-by-step explanation:</h2>
In the question,
Taking the elevation of pool along the y-axis, and length of the board along the x-axis.
On drawing the illustration in the co-ordinate system we get,
lₓ = 2 m
uₓ = 2.5 m/s
and,

So,
From the equations of the laws of motion we can state that,

So,
On putting the values we can say that,

Now,
The <u>equation of the motion in the horizontal</u> can be given by,

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

and,

Let, S = Shirt, J = Jeans
14a)
This question asks for the discount to be added after everything else.
S= 12 J=19
3S + 2J -3 = Cost with discount applied to total
^ This expression adds to costs, then takes away the $3 discount as the end.
14b)
This questions says the discount is added on every shirt, we get a similar expression:
3(S-3) + 2(J-3) = Cost with discount applied on every shirt and jeans
14c)
The difference between a) and b) is that:
> the discount in a) is applied on the total, meaning a lower discount
> the discount for b) is applied on each shirt and jeans, meaning a greater discount
14d)
If I were the shop owner I would be more specific of what the discount included, for example we don't know whether to discount each product (shirts and jeans) or only discount the total.