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Mariulka [41]
2 years ago
7

HELPPPPPPP FASTTTTTT PLSSSSSS

Mathematics
1 answer:
bulgar [2K]2 years ago
8 0

Answer:

that questons are from imagen math omg the answer is question 2

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Maya walks 9 blocks to school. If she walks 2 blocks in four minutes, how long will it take Maya to get to school.
katrin2010 [14]

Hello!

In order to find this out we should first know the ratio for the time and distance. So it takes her 4 minutes to go 2 blocks. So the ratio looks like this: 4:2. If we are trying to find 9 blocks, then multiply it by 4 and just add the other two minutes .

So in total your answer is: It takes Maya 18 minutes to walk 9 blocks.

I hope it helps!

4 0
3 years ago
Read 2 more answers
Find the quotient. Simplify your answer.<br> 7y/6 divides by z/-2
HACTEHA [7]

Answer:

-7y/3z

Step-by-step explanation:

When dividing fractions, we flip the second one so that we can multiply the 2 fractions. When we do this, we get 7y/6 * -2/z. When we multiply the numerators and denominators, we get -14y/6z. Simplifying (dividing the numerator and denominator by 2), we get -7y/3z.

7 0
3 years ago
Triangle VDG- triangle VNQ <br> What is the value of x? <br> Enter your answer in the box.
AleksAgata [21]

Question:

The image of the question is attached below.

Answer:

x = 40

Solution:

Given ΔVDG \sim ΔVNG.

DG = 207, NQ = 138, GQ = 60, QV = x

In two triangles are similar, then the measures of the corresponding sides are in proportional to each other.

$\Rightarrow\frac{DG}{NQ}=\frac{GQ}{QV}

$ \Rightarrow\frac{207}{138}=\frac{60}{x}

Do cross multiplication, we get

$ \Rightarrow{207\times x}=138\times60

$ \Rightarrow{207\times x}=8280

$ \Rightarrow{207x}=8280

Divide by 207 on both sides of the equation, we get

$ \Rightarrow\frac{{207x}}{207} =\frac{8280}{207}

$ \Rightarrow x =\frac{8280}{207}

⇒ x = 40

⇒ QV = 40

Hence the value of x is 40.

3 0
3 years ago
Read 2 more answers
HELP NOW PLEASE I GOTYA PASS
Ulleksa [173]
Following transformations on Triangle ABC will result in the Triangle A'B'C'

a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units

In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)

In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)

First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'. 

Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'. 

The same way C is translated to C'.

Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
5 0
3 years ago
Y= 5x +1<br> And <br> Y = x + 2<br><br> I need the graph
Nataly [62]

Answer:

  • 2

Step-by-step explanation:

SO you add this

5 0
3 years ago
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