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VARVARA [1.3K]
2 years ago
8

True or false: all blockchains are programmed to have the same block time (confirmation time) as each other.

Computers and Technology
1 answer:
wariber [46]2 years ago
4 0

Answer:

False

Explanation:

<em>The complexity of the hash, which is the hexadecimal number produced by the hashing process, determines the precise length of time required for block production. Thus, block times won't always be the same.</em>

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Read 2 more answers
Write a program that reads in the following data, all entered on one line with at least one space separating them: a) an integer
Rina8888 [55]

Answer:

import java.util.Scanner;

public class DataConstraint {

public static void main(String[] args) {

System.out.print("Enter month, day, year separated by spaces :");

Scanner sc=new Scanner(System.in);

int M,D,Y;

M=sc.nextInt();

D=sc.nextInt();

Y=sc.nextInt();

if(1<=M && M<=12 && 1<=D && D<=31 && Y>=1)

{

if(M==4 || M==6 ||M==9 || M==11){

if(D==31) {

System.out.println("month "+M+" can not have more than 30 days");

System.exit(0);

}

}

else if(M==2)

{

if((Y%400==0) || (Y%4==0 && Y%100!=0)) {

if(D>=30) {

System.out.println("month "+M+" cannot have "+D+" days");

System.exit(0);

}

}

else {

if(D>=29) {

System.out.println(Y+" is not a leap year, "+D+" is invalid");

System.exit(0);

}

}

}

System.out.println(M+" "+D+" "+Y+" is a valid date");

}

else{

if(1>=M || M>=12) System.out.println(M+" is not a valid month");

if(1>=D || D>=31) System.out.println(D+" is not a valid date");

if(Y<1) System.out.println("year can not be negative");

}

}

}

Explanation:

  • Use a conditional statement to check the month is between 1 and 12.
  • Check that the date is between 1 and 31 and year must be positive value.
  • If no. of days are more than 29, then the year cannot be a leap year.

4 0
3 years ago
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