First, we have to make sure that the number of columns in the first matrix is equal to the number of rows in the second matrix.
Since this is true, we can continue to solve the problem.
To multiply two matrices, multiply each row element in the first matrix by each column element in the second matrix. For example:
1*2 = 2
-3*1=-3
Then we add them to get our new matrix element.
-3+2=
-1Then we move to the next column of the second matrix.
1*3=3
-3*2=-6
-6+3=
-3Then the final column of the second matrix.
1*4=4
-3*3=-9
-9+4=-5
Our matrix so far:
We do the same for the bottom row of the first matrix.
<em>First Column</em>
2*2=4
0*1=0
4+0=
4<em>Second Column
</em>2*3=6
0*2=0
6+0=
6
<em>Third Column</em>
2*4=8
0*3=0
8+0=
8Our final matrix is:
:)
<h3>
Answer: 34</h3><h3 /><h3 /><h3 /><h3>
Step-by-step explanation: 2 – 8 - [- 4 – (-6 + 3 -9)] X ( -10 ÷2)</h3><h3>Así es como resolví esta pregunta: usé PEMDAS significa paréntesis, exponentes, multiplicación o</h3><h3> División, suma y resta...</h3><h3>Espero que la hayan resuelto bien!</h3>
Answer:
Anthony mother's has enough flour for each of Anthony's friends to get a cupcake.
Step-by-step explanation:
Let suppose that Anthony and his friend will receive at least one cupcake, which means that Anthony's mother should make at least 9 cupcakes ( dozens).
From statement we notice that quantity of cupcakes is directly proportional to the quantity of flour.
According to the recipe, the required amount of flour and cupcakes are, respectively:
Flour
Cupcakes
If Anthony's mother has 1 cup of flour at her disposal, the amount of cupcakes is obtained by simple rule of three:
In a nutshell, Anthony mother's has enough flour for each of Anthony's friends to get a cupcake.
Answer:
We are given that Commercial aircraft used for flying in instrument conditions are required to have two independent radios instead of one.
The probability of failure of one radio = 0.0026
So, the probability of failure of both radio =
Now we are supposed to find the probability that a particular flight will be safe with at least one working radio
A) the probability that a particular flight will be safe with at least one working radio = 1- 0.00000676=0.99999324
B)The usual rounding rule of three significant digits not work here because usual rounding rule of three significant digits makes it 1 which means that both radios are working properly.
C)Yes,this probability is high enough to ensure flight safety because it is close to 1
Answer: 64.08
Step-by-step explanation:
Since the 8 is in the hundredth place and there's no thousandths place the number doesn't change leaving u with 64.08