Answer:
A. neither a relation nor a function
Step-by-step explanation:
A relation between two sets is a collection of ordered pairs containing one object from each set.
A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Quadratic equations are not functions. Quadratic equations are not a function because they touch two points that is on the same y-axis. Furthermore, if they are two points that have the same x axis, then it is not a function either. It doesn't have a relation either because there are two outputs that are the same by the x axis for 3x^2 - 9x + 20. Those are x = 1 and x = 2. For proof, you can plug both of them in.
3(1)^2 - 9(1) + 20 = 14
3(2)^2 - 9(2)+ 20 = 14
Both answers have 14 as the y-axis/output. This proves that this quadratic equation is not a relation either. Therefore, this equation is neither a relation nor a function.
Answer:
Harry earns 26 and Hamish earns 20
Step-by-step explanation:
The computation of the amount earned by each one of them is shown below:
Let us assume the hairy be Y
And, the Hamish be M
It is given that Harry earns a dollar i.e more than 5/4
And, it is $2 less than 7/5
So, the equation would be
y = 1.25m + 1 ...........................(i)
And,
y= 1.4m -2 .............................(ii)
Now equal both the equations
1.25m + 1 = 1.4m - 2
3 = 0.15m
So, m = 20
Now put the values of m in any of the above equation to find out the value of Y
Y = 1.25m + 1
= 1.25 (20) + 1
= 26
Answer:
4. 27
Step-by-step explanation:
11-10=1 which is <=16
15-10=5 which is <=16
26-10=16 which is <=16
27-10=17 which isn't <=16
Therefore 27 doesn't satisfy the inequality
Answer:
x = 24.
r 
0.
Step-by-step explanation:
2. The given equation is:
a) To eliminate the fractions multiply the equation throughout by the LCM of the denominators of the fraction. In this case, the LCM of (2, 3). The LCM is 6. So, multiply the entire equation by 6.
b) Half of the difference between an integer and 4 equals the sum of one - third of the integer and 2. Find the integer.
c) We have the equation:
Multiplying throughout by 6, we get:
Therefore, the solution of the equation is 24.
3. The given equation is: 
To solve for y:
We can rearrange the equation as:
or, 
Note that we have to impose a condition on variable 
. It would be that can never be zero. i.e., 
. Otherwise, the value of 
would be undefined.
