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monitta
3 years ago
13

If f(x) = –2x^3, g(x) = 3x – 5, and h(x) = x – 1, what is f(g(h(3)))?

Mathematics
1 answer:
sveta [45]3 years ago
5 0

Put the value of x = 3 to the equation of the function h(x)


h(x)=x-1\\\\h(3)=3-1=2


Put the value of h(3) = 2 to the equation of the function g(x)


g(x)=3x-5\\\\g(2)=3\cdot2-5=6-5=1


Put the value of g(2) = 1 to the equation of the function f(x)


f(x)=-2x^3\\\\f(1)=-2\cdot1^3=-2\cdot1=-2


Answer: -2

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3 years ago
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<h3>What is the Solution to an Equation?</h3>

The solution to a given equation, is the x and y values of an ordered pair that would make the equation true, if we substitute their values into the equation.

Given the equation, y = -2x + 4, and we have (x, -2) as the solution where the value of x is the missing value in the solution, to find the value of x, substitute y = -2 into the equation and solve for x:

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