Question

If f(x) = –2x^3, g(x) = 3x – 5, and h(x) = x – 1, what is f(g(h(3)))?

Answer 1

Put the value of x = 3 to the equation of the function h(x)

$h(x)=x-1\\\\h(3)=3-1=2$

Put the value of h(3) = 2 to the equation of the function g(x)

$g(x)=3x-5\\\\g(2)=3\cdot2-5=6-5=1$

Put the value of g(2) = 1 to the equation of the function f(x)

$f(x)=-2x^3\\\\f(1)=-2\cdot1^3=-2\cdot1=-2$

Answer: -2