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Sveta_85 [38]
3 years ago
5

PLEASE HELP ME!!!!! PLEASE I WANT TO GET THIS RIGHT

Mathematics
1 answer:
klasskru [66]3 years ago
4 0

Answer:

Step-by-step explanation:

Fuji Apples: 7/6 = <u>$1.16</u>

Golden Delicious Apples: 1/0.75 = 100/75 = $<u>1.33</u>

Macintosh Apples:  <u>$2</u>

Hope this helps!      :3

plz mark as brainliest!

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tigry1 [53]
The 10th term is -1024. Just multiply 2 every time.
6 0
4 years ago
Read 2 more answers
the sum of the reciprocals of two consecutive even integers is 9/40. this can be represented by the equation shown 1/x + 1/(x+2)
Ivanshal [37]

Answer:

  8, 10

Step-by-step explanation:

Multiplying the equation by the product of the denominators, we have ...

  40(x+2) +40x = 9x(x+2)

  80x +80 = 9x^2 +18x . . . . eliminate parentheses

  9x^2 -62x -80 = 0 . . . . . . put in standard form

  9x^2 -72x +10x -80 = 0 . . . prepare to factor by grouping

  9x(x -8) +10(x -8) = 0 . . . . . factor pairs of terms

  (9x +10)(x -8) = 0

Solutions are ...

  x = -10/9  and  x = 8

The integers are 8 and 10.

_____

<em>Comment on the attachment</em>

I find a graphing calculator to be a nice tool for solving these. It finds zeros easily, so writing the equation so it equals zero is a useful first step.

5 0
4 years ago
Please help me fill in the blanks
Sedbober [7]
The attached should help you out

5 0
4 years ago
3.14r^2 what is the exponent
Sveta_85 [38]

Answer: =3.14r2

Step-by-step explanation:

the exponent is 2

8 0
4 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=9, and AC=12, find HC.
pickupchik [31]

Answer:

Step-by-step explanation:

It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get

(AC)^{2}=(AB)^{2}+(BC)^{2}

(12)^{2}=(9)^2+(BC)^2

144=81+(BC)^2

(BC)^2=63

BC=\sqrt{63}

Now, From ΔABC and ΔHBC, we have

∠ABC=∠BHC(each90)

∠ACB=∠HCB (Common)

By AA similarity, ΔABC is similar to ΔHBC.

Thus, using the similarity condition, we get

\frac{HC}{BC}=\frac{BC}{AC}

\frac{HC}{\sqrt{63}}=\frac{\sqrt{63}}{12}

HC=\frac{63}{12}=\frac{21}{4}

7 0
3 years ago
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