Answer:

Step-by-step explanation:
Given
-- degree of freedom

Required
Determine the t-value
The given parameters can be illustrated as follows:

Where

So, we have:

To solve further, we make use of the attached the student's t distribution table.
From the attached table,
The t-value is given at the row with df = 28 and
is 3.673900
Hence, 
Answer:
Because of probability, a green or red bead would be drawn 14/20 times because there are 20 total beads and adding together the numbers for green and red. From this, if you multiply by 3/3 you can see that 42/60 times it will be a green bead. A reasonable prediction for green beads would then be 42 times. Hope it helps :D
How are even supposed to work that out
Lets get common fractions between 1/10 and 1/4, so we now have the fractions 2/20 and 5/20. After we add them we have 7/20. If 35% (7/20) of the points scored is 21, then total points scored is 60. (21 / .35)
Answer: 9/10
Step-by-step explanation: