Question

6. A waiter in a restaurant has eight booths in his station. How many different arrangements are possible for the hostess to seat customers at the waiter’s booths if order is important? (3 po

Answer 1

Answer:

8 possible seats

Step-by-step explanation:

Given

$n = 8$ ---booths

$r = 1$ --- hostess

Required

Number of possible seats (order is important)

If order is important, then we solve using permutation

i.e.

$^nP_r = \frac{n!}{(n - r)!}$

So, we have:

$^{8}P_1 = \frac{8!}{(8 - 1)!}$

This gives:

$^{8}P_1 = \frac{8!}{7!}$

Expand

$^{8}P_1 = \frac{8*7!}{7!}$

$^{8}P_1 = 8$

Answer 2

Answer:

8

Step-by-step explanation:

pure guess and give brainliest to the other person