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ivann1987 [24]
4 years ago
14

Brady jogs laps around a circular park with a fountain at the center. Which table could represent Brady’s distance from the foun

tain after jogging around the path for a number of minutes?
Mathematics
2 answers:
Stels [109]4 years ago
5 0

Answer:

the answer is number 3.

Step-by-step explanation:

Arlecino [84]4 years ago
4 0
Since the fountain is at the center of the circular park, the distance from the fountain to the circular path that Brady jogs on will always be the same.

The distance from the fountain to the path of the park will serve as the radius of the circular park.

In the event that the circumference of the park will be given, we can solve for the radius using this formula:

Radius = Circumference / 2π

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PLEASE HURRY!!!!! Which statement describes the situation shown in the graph?
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Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company
erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that n = 16

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that p = 0.5

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0

P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002

P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018

P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0
3 years ago
Which of the following options have the same value as 30\%30%30, percent of 818181?
Nataly_w [17]

Answer:

Option B is correct = 0.3 \times 81

Step-by-step explanation:

<u>The complete question is:</u> Which of the following options have the same value as 30% of 81?

Group of choices is:

(A) \frac{30}{100}\times 81 \times 100

(B) 0.3 \times 81

(C) 0.03 \times 81

(D) \frac{3}{10}\times 81 \times 10

(E) 30 \times 81

Now, the expression given to us is 30% of 81.

Simplifying the above expression we get;

   30% of 81  =  \frac{30}{100} \times 81

                     =  \frac{3}{10} \times 81  =  0.3 \times 81

Now, we will solve each of the given options and then see which option matches with our calculation.

Option (A) is given;

\frac{30}{100}\times 81 \times 100  =  30 \times 81

This doesn't match with our answer, so this option is not correct.

Option (B) is given;

0.3 \times 81  

<u><em>This matches with our answer, so this option is correct.</em></u>

Option (C) is given;

0.03 \times 81  

This doesn't match with our answer, so this option is not correct.

Option (D) is given;

\frac{3}{10}\times 81 \times 10  =  3 \times 81

This doesn't match with our answer, so this option is not correct.

Option (E) is given;

30 \times 81  

This doesn't match with our answer, so this option is not correct.

6 0
4 years ago
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