A rectangle has an area of 120cm2. It's length and width are whole numbers.

Round 287.9412 to the nearest tenth. Do not write extra zeros.

goldenfox [79]

Salutations!

Round 287.9412 to the nearest tenth.

Lets solve this!

To round to the nearest tenth, you need to know the tenth place--------

In the number, 287.9412, nine is in the tenth place. You need also make sure whether the number next to 9 is greater than 5 or not.

287.9412 =287.941=287.94=287.9=288=290

Thus, your answer is 290.

Hope I helped.

3 0

3 years ago

Read 2 more answers

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

(c) Here, also 8 computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

Find the length of abc express in terms of pie

Hitman42 [59]

You should choose c because it makes the most sense out of all of them

6 0

3 years ago

During halftime of a basketball game, a sling shot launches T-shirts at the crowd. A T-shirt is launched from a height of 4 f

Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is $4 + 64\cdot t - 16 \cdot t^{2}$

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

$h = 4 + 64\times 2 - \frac{1}{2} \times 32 \times 2^{2}$

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

$h = h_1 + u\cdot t - \frac{1}{2} \cdot g \cdot t^{2}$

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

$h =4 + 64\cdot t - \frac{1}{2} \times 32 \cdot t^{2} = 4 + 64\cdot t - 16 \cdot t^{2}$ .

6 0

3 years ago

Find the measure of the missing angles

vekshin1

Answer:

H: 119 degrees.

G: 61 degrees.

M: 54 degrees.

K: 126 degrees.

Step-by-step explanation:

6 0

2 years ago