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Varvara68 [4.7K]
3 years ago
9

Please help i have to turn in in 6 mins...thanks :)

Mathematics
1 answer:
denis23 [38]3 years ago
4 0

Answer: ~5

Step-by-step explanation:

It's been awhile for me but I think you do sin=opp/hyp

sin(45)=3sqrt(2)/x

x = 3sqrt(2)/sin(45) = (approx) 5

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2x + 4y = 14 and 3x - 4y = -39
miskamm [114]

Answer:

x = 1 y= 3

Step-by-step explanation:

Multiply each equation by the value that makes the coefficients of y opposite.

Simplify.

Add the two equations together to eliminate y from the system.

Divide each term by 8 and simplify.

Substitute the value found for x into one of the original equations, then solve for y.

The result can be shown in multiple forms.

Point Form:

(1,3)

Equation Form:

x=1 ,y=3

.

7 0
3 years ago
PLS HELP WILL MARK BRAINLIEST, PLS HURRY
Juli2301 [7.4K]
Multinomial, i believe
hope this helps!
4 0
2 years ago
Consider the exponential function g(x) = 1,296 x .
AleksandrR [38]
1296(-1.75)= -2268;
 1296(-1)= -1296;
 1296(-0.25)= -324;
 1296(0)=0;
 1296(0.25)=324;
 1296(0.5)=648;
1296(0.75)=972);
 1296(1)=1296
4 0
3 years ago
alan drew a picture with four sides and four angles. all four sides are equal none of the angles are right angles. What is the s
tankabanditka [31]
Rhombus is the answer.............
4 0
3 years ago
Read 2 more answers
Find an equation for the line that passes through the points (-1,2) and (5,5)
sesenic [268]

Answer:

-The equation for the problem:

y = \frac{1}{2}x + \frac{5}{2}

Step-by-step explanation:

-First, you need determine the slope of a line:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} (where (x_{1},y_{1}) is the first coordinate and (x_{2},y_{2}) is the second coordinate).

-Use both points (-1,2) and (5,5) for the formula:

m = \frac{5-2}{5+1}

m = \frac{3}{6}

m = \frac{1}{2}

-After you have found the slope, use the point-slope formula and use the slope \frac{1}{2} and the first coordinate, which is (-1,2), to solve the equation and put it in slope-intercept form:

y-y_{1} = m (x-x_{1})

y-2 = \frac{1}{2}  (x+1)

-Solve:

y-2 = \frac{1}{2}  (x+1)

y-2 = \frac{1}{2}x + \frac{1}{2}

y = \frac{1}{2}x + \frac{5}{2}

So, therefore the equation is y = \frac{1}{2}x + \frac{5}{2} .

8 0
3 years ago
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