Answer:
or 
Step-by-step explanation:
4x + 15 < 40
Subtract 15 from both sides
4x + 15 - 15 < 40 - 15
4x < 25
Divide both sides by 4
4x/4 < 25/4
x < 6.25
or
x < 6 1/4
The problem statement gives a relation between the amount removed from one bag and the amount removed from the other. It asks for the amount remaining in each bag. Thus, there are several choices for variables in this problem, some choices resulting in more complicated equations than others.
Let's do it this way: let x represent the amount remaining in bag 1. Then the amount removed from bag 1 is (100-x). The amount remaining in bag 2 is 2x, so the amount removed from that bag is (100-2x). The problem statement tells us the relationship between amounts removed:
... (100 -x) = 3(100 -2x)
... 100 -x -3(100 -2x) = 0 . . . . . . subtract the right side
... 5x -200 = 0 . . . . . . . . . . . . . . eliminate parentheses and collect terms
... x -40 = 0 . . . . . . . . . . . . . . . . .divide by 5
... x = 40 . . . . . . . . . . . . . . . . . . . add 40
- 40 kg is left in the first bag
- 80 kg is left in the second bag
_____
<u>Check</u>
The amount removed from the first bag is 60 kg. The amount removed from the second is 20 kg. The amount removed from the first bag is 3 times the amount removed from the second bag, as described.
In hexadecimal/base-16, we have B₁₆ = 11, C₁₆ = 12, and D₁₆ = 13, so
4D₁₆ = 4 × 16¹ + 13 × 16⁰ = 77
and
BC2₁₆ = 11 × 16² + 12 × 16¹ + 2 × 16⁰ = 3010
Answer:
5/2
Step-by-step explanation:
Move the 5^-3 to the denominator and add the exponents of like coefficents
Answer:
D- All the residents of the city.
Step-by-step explanation:
