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Ksenya-84 [330]
3 years ago
11

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

Step-by-step explanation:

Given the expression

\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)

Remove parentheses:  (a)=a

=-t^4-5t^3-10t^2+9t^3+3t^2-1

Group like terms

=-t^4-5t^3+9t^3-10t^2+3t^2-1

Add similar elements        

=-t^4-5t^3+9t^3-7t^2-1         ∵ -10t^2+3t^2=-7t^2

Add similar elements        

=-t^4+4t^3-7t^2-1                  ∵  -5t^3+9t^3=4t^3

Thus, the equivalent expression in simplified form:

\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1

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Answer:

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Step-by-step explanation:

2x+10=3x-10

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Add 10 to each side

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\huge{\underline{\underline{\sf{\red{Required\:Solution:-}}}}}

<h3>Volume of cylinder B is greater.</h3>

<h2>For Cylinder A :-</h2>

\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{7}{2}cm}}

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Substitute the values and simplify it

\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times \bigg(\frac{7}{2}^{2} \bigg)\times14}}

\large{\boxed{\sf{\orange{= 539 cm^{3}}}}}

<h2>For Cylinder B:-</h2>

\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{14}{2}cm=7cm}}

\displaystyle{\sf{\:\:\:\:\:\:\:\:h(height)\:=\: 7cm}}

\displaystyle{\boxed{\sf{ Volume\:=\: \pi r^{2}h}}}

Substitute the values and simplify it.

\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times (7^{2})\times7}}

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<h3>By actual calculation of volumes of both the cylinders, it is verified that the volumes of cylinder B is greater.</h3>

━━━━━━━━━━━━━━━━━━━━━━━━━━

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