The solution to the following system of linear equations lies in which quadrant?

Beverly is painting a mural on a 1-square-meter section of a wall. She has completed a rectangular part of the mural that's is 5

yawa3891 [41]

Answer:

0.21 square meter

Step-by-step explanation:

Area of the section of wall = 1 square meter

Dimension of part of mural completed = $\frac{1}{4}$ meter by $\frac{5}{6}$ meter

Part of the mural completed = Area of the rectangular part of mural completed

But,

Area of a rectangle = length x width

So that,

Part of the mural completed = length x width

= $\frac{1}{4}$ x $\frac{5}{6}$

= $\frac{5}{24}$

= 0.2083

Part of the mural completed = 0.21 square meter

The part of the mural that has been completed by Beverly is 0.21 square meter.

7 0

2 years ago

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How to find (c,d,e)<br>Please do a step by step working.Thank you.

Natasha2012 [34]

(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
   $\frac{t + 1}{2}$ = y
Answer for (a): $g^{-1}(t)$ = $\frac{t + 1}{2}$

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: $y =\frac{t - 3}{4}$

Answer for (b): $h^{-1}(t)$ = $\frac{t - 3}{4}$

(c)
$g^{-1} ( h^{-1}(t)) = g^{-1} (\frac{t - 3}{4})$
replace all t's in the $g^{-1}(t)$ equation with $\frac{t - 3}{4}$
$g^{-1} (\frac{t - 3}{4})$ = $\frac{ \frac{t-3}{4} + 1}{2}$
= $\frac{ \frac{t-3}{4} + \frac{4}{4}}{2}$ = $\frac{ \frac{t - 3 + 4}{4}}{2}$ = $\frac{ \frac{t + 1}{4}}{2} = \frac{t + 1}{8}$
Answer for (c): $g^{-1} ( h^{-1}(t))$ = $\frac{t + 1}{8}$

(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
   y = 8 t - 1
   t = 8y - 1
t + 1 = 8y
$\frac{t + 1}{8}$ = y
Answer for (e): inverse of h(g(t)) = $\frac{t + 1}{8}$

8 0

2 years ago

How many square feet of outdoor carpet will we need for this hole

Goshia [24]

Answer:

30

Step-by-step explanation:

6 0

2 years ago

PLZ ANSWER QUICK!!!

alexira [117]

Answer; c^2 = a^2 + b^2

c = 17 inches

a = 8 inches

b^2 = c^2 – a^2

b^2 = 17^2 – 8^2

b^2 = 289 – 64

b^2 = 225

b = square root of 225

b = 15 inches ≈ c.

5 0

3 years ago

The net of a rectangular prism is shown below.

Mamont248 [21]

Answer:

28

Step-by-step explanation:

Using a net to find the surface area of a rectangular prism

Finding the areas of each of the rectangles and squares of the net of a rectangular prism and adding up those areas gives the surface area or total surface area of the prism.

For example, if the length of one side of the cube 4 units then the area of one its face is 4 × 4 = 16 square units. From the net, we can see that there are six equal faces and so we get the total surface area is 6 × 16 = 96 square units.

Surface Area of a Rectangular Prism using Nets

A rectangular prism or cuboid is formed by folding a net as shown −

Cuboid

We can see from the net that there are two rectangles with dimensions 3 cm by 6 cm, two rectangles with dimensions 2 cm by 6 cm and two rectangles with dimensions 2 cm by 3 cm. The total surface area is then

2 × 3 × 6 + 2 × 2 × 6 + 2 × 2 × 3 = 72 cm2

Example 1:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism in Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 6 ; w = 5; h = 3

Step 2:

Surface area of given prism = 26×5+6×3+3×5

= 230+18+15

= 126 square cm

Example 2:

Find the surface area of the given rectangular prism in square cm.

Rectangular Prism Square cm

Solution

Step 1:

Using net, the surface area of a rectangular prism

= 2lw+wh+lh; l = 5; w = 6; h = 4

Step 2:

Surface area of given prism = 25×6+5×4+6×4

= 230+20+24

= 148 square cm

6 0

2 years ago

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