Question

Plzzzzzzzzzzzzz helpppppppppppppp

Answer 1

Heyyyoooooooooo I got youuuuuu giveeee meeee a second pleaseeeeeee

Answer 2

Answer:

Question 25:

$6$

Question 19:

$16$

Step-by-step explanation:

Question 25:

$\frac{x}{12} + \frac{y}{3} = 2$

$\frac{y}{3 } = 2 - \frac{x}{12}$

$y = 3( 2 - \frac{x}{12} )$

$y = 6 - \frac{x}{4}$

$y = - \frac{x}{4} + 6$

Question 19:

${x}^{2} - 8x + c$

${x}^{2} + c - 18$

To find the c value ,

$c = ( \frac{b}{2} {)}^{2}$

divide the coefficient of x by 2 and square the result.

$( - 1 \times 4 {)}^{2}$

$( - 4 {)}^{2}$

$16$

Hope it is helpful....