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lawyer [7]
3 years ago
13

Question 26: write the equation that describes the line with slope=5 and y-intercept =8 in slope intercept form.example: y=mx+b

Mathematics
1 answer:
elixir [45]3 years ago
3 0

Answer:

y = 5x + 8

Step-by-step explanation:

Start with y = mx + b:  general slope-intercept form, equation of a line:

Replace m with 5, y with 8 and x with 0 (since the y-intercept is (0, 8):

8 = 5(0) + b.  Then b must be 8, and the desired equation is

y = 5x + 8

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I need with this and please show workkk
trasher [3.6K]

Answer:

1. ∠1 = 120°

2. ∠2 = 60°

3. ∠3 = 60°

4. ∠4 = 60°

5. ∠5 = 75°

6. ∠6 = 45°

Step-by-step explanation:

From the diagram, we have;

1. ∠1 and the 120° angle are corresponding angles

Corresponding angles are equal, therefore;

∠1 = 120°

2. ∠2 and the 120° angle are angles on a straight line, therefore they are supplementary angles such that we have;

∠2 + 120° = 180°

∠2 = 180° - 120° = 60°

∠2 = 60°

3. Angle ∠3 and ∠2 are vertically opposite angles

Vertically opposite angles are equal, therefore, we get;

∠3 = ∠2 = 60°

∠3 = 60°

4. Angle ∠1 and angle ∠4 an=re supplementary angles, therefore, we get;

∠1 + ∠4 = 180°

∠4 = 180° - ∠1

We have, ∠1 = 120°

∴ ∠4 = 180° - 120° = 60°

∠4 = 60°

5. let the 'x' and 'y' represent the two angles opposite angles to ∠5 and ∠6

Given that the two angles opposite angles to ∠5 and ∠6 are equal, we have;

x = y

The two angles opposite angles to ∠5 and ∠6 and the given right angle are same side interior angles and are therefore supplementary angles

∴ x + y + 90° = 180°

From x = y, we get;

y + y + 90° = 180°

2·y = 180° - 90° = 90°

y = 90°/2 = 45°

y = 45°

Therefore, we have;

∠4 + ∠5 + y = 180° (Angle sum property of a triangle)

∴ ∠5 = 180 - ∠4 - y

∠5 = 180° - 60° - 45° = 75°

∠5 = 75°

6. ∠6 and y are alternate angles, therefore;

∠6 = y = 45°

∠6 = 45°.

6 0
3 years ago
If PQRS is a rhombus, find m
egoroff_w [7]

Answer:

m<PQR = 82°

Step-by-step explanation:

In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.

Therefore:

(4x - 27)° = (2x + 7)°

Solve for x

4x - 27 = 2x + 7

Collect like terms

4x - 2x = 27 + 7

2x = 34

Divide both sides by 2

2x/2 = 34/2

x = 17

✔️m<PQR = (4x - 27) + (2x + 7)

Plug in the value of x

m<PQR = (4*17 - 27) + (2*17 + 7)

m<PQR = 41 + 41

m<PQR = 82°

6 0
3 years ago
Janine found a perfect sundress for 30% off. The original price, before tax, was $60. What was the sale price of the dress befor
Mazyrski [523]
60 * .30 = 18

60 - 18 = $42
7 0
3 years ago
Estimate the student's walking pace, in steps per minute, at 3:20 p.m. by averaging the slopes of two secant lines from part (a)
ehidna [41]

This question is incomplete, the complete question is;

A student bought a smart-watch that tracks the number of steps she walks throughout the day. The table shows the number of steps recorded (t) minutes after 3:00 pm on the first day she wore the watch.

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

a) Find the slopes of the secant lines corresponding to the given intervals of t.

1) [ 0, 40 ]

11) [ 10, 20 ]

111) [ 20, 30 ]

b) Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part (a). (Round your answer to the nearest integer.)

Answer:

a)

1) for [ 0, 40 ], slope is 96

11) for [ 10, 20 ],  slope is 86.3

111) for  [ 20, 30 ], slope is 116.4

b) the student's walking pace is 101 per min

Step-by-step explanation:

Given the data in the question;

t (min)       0          10          20         30         40

Steps   3,288    4,659    5,522    6,686    7,128

SLOPE OF SECANT LINES

1) [ 0, 40 ]

slope =  ( 7,128 - 3,288 ) / ( 40 - 0

= 3840 / 40 = 96

Hence slope is 96

11)  [ 10, 20 ]

slope = ( 5,522 - 4,659 ) / ( 20 - 10 )

= 863 / 10 = 86.3

Hence slope is 86.3

111)  [ 20, 30 ]

slope = ( 6,686 - 5,522 ) / ( 30 - 20 )

= 1164 / 10 = 116.4

Hence slope is 116.4

b)

Estimate the student's walking pace, in steps per minute, at 3:20 pm by averaging the slopes of two secant lines from part .

Since this is recorded after 3:00 pm

{ 3:20 - 3:00 = 20 }

so t = 20 min

so by average;

we have ( [ 10, 20 ] + [ 20, 30 ] ) /2

⇒ ( 86.3 + 116.4 ) / 2

= 202.7 /2

= 101.35 ≈ 101

Therefore, the student's walking pace is 101 per minutes

3 0
3 years ago
Plz help itz due tommorow plz<br><br>question in pic
vekshin1

Answer:

The answer is -2

Step-by-step explanation:

-6 means you go on the left and then you subtract -2 which means go backward 2 Soooo you got the right answer.

8 0
3 years ago
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