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2 years ago

5

The midpoint between x and 27 is -3. What is x?

1 answer:

Alex_Xolod [135]2 years ago

6 0

Answer:

-33

Step-by-step explanation:

well you can use mid point formula and solve for x

or count how many it takes to get from -3 to 27 and add that to -3 the other direction

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What is equivalent to the equation to 1/4 (8 + 6z + 12) ?

Fed [463]

1/4 (8 + 6z + 12)

------------------------------------------------------------
Combine like terms :
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1/4 (6z + 20)

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Apply distributive property :
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1/4(6z) + 1/4(20)
3/2z + 5

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Answer: 3/2z + 5
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3 years ago

Use dimensional analysis to convert the measurements.

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Step-by-step explanation:

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3 years ago

Which of the following points are solutions to the equation 3x-4y-8=12

liberstina [14]

The answer for the equation is (4, -2)

8 0

3 years ago

nasty-shy [4]

Answer:

B

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5 0

2 years ago

Read 2 more answers

To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

6 0

3 years ago