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nata0808 [166]
3 years ago
11

Hey guys what is the factors of 8 (i need all of them)

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

1,2,4,8

Step-by-step explanation:

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A science fair poster is very rectangular 3 feet long and 2 feet wide what is the area of the poster in square inches
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You want to do base × height to get your answer
3×2 = 6
So the area of the poster is 6 sq in.


If this helps pls mark brainliest pts
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What's the number of people left to play at 10 of <br> 15 have played
erma4kov [3.2K]

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5 people will be left to play

5 0
3 years ago
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Four members from a 45​-person committee are to be selected randomly to serve as​ chairperson, vice-chairperson,​ secretary, and
wariber [46]

Answer:

3575880

Step-by-step explanation:

We need to use Permutation method,

nPr= \frac{n!}{(n-r)!}

Where n is the sample of size and r the combination considered, so

n=45\\r=4\\45P4= \frac{45!}{(45-4)!}\\45P4 = 3575880

There is 3575880 possibilities to make leadership structures in that committee

6 0
3 years ago
Geometry, please answer question ASAP
Aleonysh [2.5K]

Answer:

A

Step-by-step explanation:

The inscribed angle IJK is half the measure of its intercepted arc, so

arc IK = 2 × 75° = 150°

The 3 arcs sum to  360° , then

arc IJ = 360° - (150 + 110)° = 360° - 260° = 100° → A

8 0
3 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
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