All categories

3 years ago

Determine if the following relations are functions. If they are functions, also state the domain and range.

Mathematics

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

desculpa mas eu não sei a resposta mais eu vou ver se posso te ajudar taaa

You might be interested in

Mozart's Music Store rents trombones for $34 a month. Bach's Music Store rents trombones for $30 per month plus a yearly fee of

jeka94

Answer:

Step-by-step explanation:

Let $M(x)$ be the cost of renting from Mozart's Music Store for $x$ years, and $B(x)$ be the cost of renting from Bach's Music Store for $x$ years.

From the problem statement, we can come up with the following equations:

$M(x) = 34(12x)$

$B(x) = 30(12x) + 48x$

Plugging in $x = 9$ for each equation, we can get the answer:

$M(9) = 34(12 * 9)$

$M(9) = 34(108)$

$M(9) = 3672$

$B(9) = 30(12 * 9) + 48(9)$

$B(9) = 30(108) + 432$

$B(9) = 3240 + 432$

$B(9) = 3672$

From this, we can see that the value is equal for both stores.

4 0

3 years ago

Evaluate the expression.<br><br> (1.5)2(1.5)<br> −2⋅(1.5)4

aleksklad [387]

Is this (1.5)2(1.5) / -2(1.5)4? or is it (1.5)2(1.5) - 2(1.5)4?

First option:
4.5/-12 = -0.375

Second option
4.5-12 = -7.5

8 0

3 years ago

What is the most efficient first step to isolate the variable term on one side of this equation?

stich3 [128]

Answer: subtract 5 from both sides

Explanation: get rid of the 5 before moving on to isolating the variable

3 0

3 years ago

You want to test the effect of light on the distribution of Artemia in your 35cm long testing chamber. If you measure the light

Dvinal [7]

Answer:

64.3 lumens

Step-by-step explanation:

Data provided in the question:

Length of the testing chamber = 35 cm

Light at one end = 10 lumens

Light at other end = 200 lumens

now,

since the variation is linear,

therefore, the gradient of the variation

= $\frac{200-10}{35}$

= 5.43

also,

the darkest end is the end with 10 lumens

therefore,

The lumens at 10 cm from the darkest end

= 10 + 5.43(10)

= 10 + 54.3

= 64.3 lumens

6 0

3 years ago

ſ x - 5y = -9( 4x + 4y = - 12Step 1 of 2: Determine if the point (-4,1) lies on both of the lines in the system of equations by

Phoenix [80]

Given:

$\begin{gathered} x-5y=-9\ldots\ldots(1) \\ 4x+4y=-12\ldots\text{.}\mathrm{}(2) \end{gathered}$

The given point is (-4,1)

Let's check the ordered pair (-4,1) in the first equation

$\begin{gathered} x-5y=-9 \\ (-4)-5(1)=-9 \\ -4-5=-9 \\ -9=-9 \end{gathered}$

Hence, (-4,1) is a solution of the first equation x-5y=-9.

Now, let's check (-4,1) in the second equation.

$\begin{gathered} 4x+4y=-12 \\ 4(-4)+4(1)=-12 \\ -16+4=-12 \\ -12=-12 \end{gathered}$

So, (-4,1) is a solution of the second equation 4x+4y=-12.

Hence, (-4,1) is a solution of both equation in the system, then it is a solution to the overall system.

3 0

1 year ago