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Zolol [24]
3 years ago
15

Alex had 45 toy cars he put 26 toy in a box how many toy cars are not in the box ?

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0
19 toy cars arent in the box

erastovalidia [21]3 years ago
3 0
19 Toy Cars. Hope this helps!
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What is the y-value when x equals 25? y= 650 - 15(x)
yarga [219]

Answer:

y= 275 when x is 25

5 0
3 years ago
Step by step how to solve ? 16x^2-10.3x+10=
Stella [2.4K]

Answer:

it is not possible result is not given so it is not possible

8 0
3 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
(07.06) There are currently 4 people signed up to play on a baseball team. The team must have at least 9 players.
beks73 [17]

A graph which includes the possible values for number of people who can still sign up for the team is: B. number line with closed circle on 5 and shading to the right.

<h3>What is a number line?</h3>

A number line can be defined as a type of graph with a graduated straight line which contains numerical values (positive and negative numbers) that are placed at equal intervals along its length.

Let the number of people who can still sign up for the team be represented by x. Thus, the inequality is given by:

x + 4 ≥ 9

x ≥ 9 - 4

x ≥ 5.

This ultimately implies that, there could be five (5) or more people that can still sign up for the team and a graph which includes these possible values is a number line with closed circle on five (5) and shading to the right because it can get larger.

Read more on number line here: brainly.com/question/24644930

#SPJ1

8 0
2 years ago
There are 30 coins all dimes and quarters on the table worth
nignag [31]

Answer:

We can set up a system of equations.

x + y = 111

0.25x + 0.10y = 18.30

x + y = 111

Subtract 'y' to both sides:

x = -y + 111

Plug in '-y + 111' for 'x' in the 2nd equation:

0.25(-y + 111) + 0.10y = 18.30

Distribute 0.25 into the parenthesis:

-0.25y + 27.75 + 0.10y = 18.30

Combine like terms:

-0.15y + 27.75 = 18.30

Subtract 27.75 to both sides:

-0.15y = -9.45

Divide -0.15 to both sides:

y = 63

Plug this back into any of the two equations to find the 'x' value.

x + y = 111

x + 63 = 111

Subtract 63 to both sides:

x = 48

So there are 48 quarters and 63 dimes.

Step-by-step explanation:

Hope This Helps!

3 0
3 years ago
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