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Paraphin [41]
3 years ago
10

5x=-y+6 solve for y when x =1,2,3

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0
When x = 1
5(1) = -y + 6
5 = -y + 6
y = 6 - 5 = 1

When x = 2
5(2) = -y + 6
10 = -y + 6
y = 6 - 10 = -4

When x = 3
5(3) = -y + 6
15 = -y + 6
y = 6 - 15 = -9
creativ13 [48]3 years ago
4 0
Test 1 in for x

5(1)= -y +6
5= -y+6
Subtract 6 from both sides

-1 = -y

Divide by -1 to get 1=y

x=2
5(2)= -y +6
10= -y+6

Subtract 6 from both sides
4= -y

Divide by -1

-4=y
---------------------------
X=3
5(3)= -y +6
15= -y +6

Subtract 6 from both sides
9= -y

Divide by -1
-9 = y
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Solve the system of equations using substitution<br> 4x + 2y = 16<br> =−12+5
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Answer:

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Step-by-step explanation:

\begin{bmatrix}4x+2y=16y\\ y=-\frac{1}{2}x+5\end{bmatrix}

\mathrm{Substitute\:}y=-\frac{1}{2}x+5

\begin{bmatrix}4x+2\left(-\frac{1}{2}x+5\right)=16\left(-\frac{1}{2}x+5\right)\end{bmatrix}

Simplify

\begin{bmatrix}3x+10=16\left(-\frac{1}{2}x+5\right)\end{bmatrix}

Isolate x for 3x+10=16(-1/2x+5): x=\frac{70}{11}

\mathrm{For\:}y=-\frac{1}{2}x+5

\mathrm{Substitute\:}x=\frac{70}{11}

y=-\frac{1}{2}\cdot \frac{70}{11}+5

-\frac{1}{2}*\frac{70}{11}+5=\frac{20}{11}

y=\frac{20}{11}

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=\frac{70}{11},\:y=\frac{20}{11}

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