-1.6
-1.35
0.3
0.5
Top to bottom, top is the lowest
<h3>
Answer: Largest value is a = 9</h3>
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Work Shown:
b = 5
(2b)^2 = (2*5)^2 = 100
So we want the expression a^2+3b to be less than (2b)^2 = 100
We need to solve a^2 + 3b < 100 which turns into
a^2 + 3b < 100
a^2 + 3(5) < 100
a^2 + 15 < 100
after substituting in b = 5.
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Let's isolate 'a'
a^2 + 15 < 100
a^2 < 100-15
a^2 < 85
a < sqrt(85)
a < 9.2195
'a' is an integer, so we round down to the nearest whole number to get 
So the greatest integer possible for 'a' is a = 9.
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Check:
plug in a = 9 and b = 5
a^2 + 3b < 100
9^2 + 3(5) < 100
81 + 15 < 100
96 < 100 .... true statement
now try a = 10 and b = 5
a^2 + 3b < 100
10^2 + 3(5) < 100
100 + 15 < 100 ... you can probably already see the issue
115 < 100 ... this is false, so a = 10 doesn't work
Answer:
2 Committees
Step-by-step explanation:
2 Committees and 3/4 of a committee
There are only 11 teachers so that means only 2 committees can be filled with 4 teachers if that is the max amount per committee.
There are more than enough students so no need to worry on them.
11 divided by 4 = 2.75
Answer:
B) Distribute 1.2 to 6.3 and –7x
D) Combine 3.5 and 7.56
E) Subtract 11.06 from both sides
2x^3
2 can fit into 10 and 46
and you can take 3 out of 3 and 5