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Andru [333]
3 years ago
8

In the diagram below, OPis circumscribed about quadrilateral ABCD. What is the value of x?

Mathematics
1 answer:
Nikitich [7]3 years ago
7 0

9514 1404 393

Answer:

  C.  82

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary. So ...

  (x + 10°) + 88° = 180°

  x = 180° -98°

  x = 82°

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3(g + 4) = 9<br> Need help
andrezito [222]

Answer:

g=-1

Step-by-step explanation:

3(g+4)=9

Divide both sides by 3.

g+4=  9/3

Divide 9 by 3 to get 3.

g+4=3

Subtract 4 from both sides.

g=3−4

Subtract 4 from 3 to get −1.

g=−1

7 0
3 years ago
Read 2 more answers
5. Find the measures of the following. Round to the nearest whole number. (2 points)
chubhunter [2.5K]

Answer:

HT = 17 cm

<T = 58°

<H = 32°

Step-by-step explanation:

✔️Find HT:

Since it's a right triangle, we would apply the Pythagorean Theorem given as c² = a² + b²

Where,

a = HW = 15 cm

b = WT = 8 cm

c = HT

Plug in the values:

HT² = 15² + 8²

HT² = 289

HT = √289

HT = 17 cm

✔️Find <T by applying trigonometric ratio formula:

Recall: SOH CAH TOA

Reference angle (θ) = <T

HW = 15 cm = Opposite side length

WT = 8 cm = Adjacent side length

Apply CAH:

Cos θ = Adj/Hyp

Substitute

Cos T = 8/15

T = cos^{-1}(0.5333)

T ≈ 58°

✔️Find <H:

Sun of interior angles of a triangle = 180°

Therefore,

m<H + m<T + m<W = 180°

Substitute

m<H + 58° + 90° = 180°

m<H + 148° = 180°

m<H = 180° - 148°

m<H = 32°

4 0
4 years ago
What would be a creative science project name for a project about whether meat cooks faster cut or uncut? you can search it up.?
fomenos
This isn’t math, but I’ll still help.

I’ll give a few options.

1. Juicy Protein: Blazing Cuts
2. Chopped Meals: Delicious Dish
3. Packed on Tender Meats
4. Cut or Uncut, Tender Cooking
5. Speed Cook: Slice or No?

Hope this helped!
4 0
3 years ago
What is the answer, I don't get it.
Dmitriy789 [7]

Answer:

A, E, and C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
My motor boat normally travels at 24 km h-1 instill water. One day I travelled 36 km against a constant current in a river. If I
11Alexandr11 [23.1K]

36=v-c

48=v+c

36+c=v

48-c=v

36+c=48-c

2c=48-36

2c=12

C=6

4 0
3 years ago
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