3 years ago

100 POINTS PLEASE HELP Please be accurate with this too.

Mathematics

2 answers:

zmey [24]3 years ago

5 0

Here you go! I hope you can read it

Yanka [14]3 years ago

3 0

Answer:

The answer is A :)

Step-by-step explanation:

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HELP ME PLEASE AHHHHH!!!

FrozenT [24]

If im not wrong...D.... would be the answer

5 0

3 years ago

Commemorative coins come in packs of 15,while coin holders come in packs of 25. What are the least numbers of packs you should b

kozerog [31]

The least common multiple of 25 and 15 is 75. You'd do _ x 25 = 75 and _ x 15 = 75. The answer would be 3 and 5, so 5 packs of coins and 3 packs of coin holders.

7 0

3 years ago

Read 2 more answers

Pls. Help me to solve this math problem.

Tju [1.3M]

$\bf (\stackrel{x_1}{x}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-(-7)}{-6-x}=\stackrel{\textit{slope}}{-\cfrac{15}{7}}\implies \cfrac{8+7}{-6-x}=-\cfrac{15}{7} \\\\\\ \cfrac{15}{-6-x}=-\cfrac{15}{7}\implies 105=(-6-x)(-15)\implies 105=90+15x \\\\\\ 15=15x\implies \cfrac{15}{15}=x\implies 1=x$