The given problem is :
(6x^4 + 15x^3 − 2x^2 + 10x − 4) ÷ (3x^2 + 2)?
now we can write expression (6x^4 + 15x^3 − 2x^2 + 10x − 4) as
(6x^4 + 4x^2 + 15x^3 + 10x - 6x^2 -4)
we have somehow arrange the expression in a way that 3x^2 + 2 is common
now the expression comes out to be
2x^2(3x^2 + 2) + 5x(3x^2+2) -2(3x + 2) / (3x^2+2)
After dividing final result comes out to be (2x^2 + 5x -2)
It depends on which variable is eliminated.
If you multiply the second equation by -1 and eliminate the y:
3x - y = 7
-6x + y = -10
-3x = -3 or x = 1
If you multiply the first equation by -2 and eliminate the x:
-6x + 2y = -14
6x - y = 10
y = -4
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Answer:
Rectangle: 112m
Trapezoid: 28m
Step-by-step explanation:
The area of the rectangle is 8*14, which is 112. The area of the trapezoid is ((base1 + base2)* height)/2. That is ((4+10)*4)/2, which is 28.
