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3 years ago

A linear function always has a _______? What is the blank

Mathematics

1 answer:

jonny [76]3 years ago

3 0

Answer:

i bellive the answer is a function

Step-by-step explanation:

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Uhh help lol 5.3x + y = 28.5 4.2x + 3.1y = 27.2 find x and y

navik [9.2K]

Answer:

x = 5, y = 2

Step-by-step explanation:

First, isolate y in the top equation.

$y = -5.3x+28.5$

Next, substitute y in the bottom equation.

$4.2x + 3.1(-5.3x + 28.5) = 27.2$

$5.3x + y = 28.5$

Simplify.

$4.2x + -16.43x + 88.35 = 27.2$

Combine like terms.

$-12.23x + 88.35 = 27.2$

Isolate x on one side.

$-12.23x = -61.15$

Isolate x.

$x = 5$

Substitute x into $5.3x + y = 28.5$

$5.3(5) + y = 28.5$

Simplify.

$26.5 + y = 28.5$

Isolate y.

$y = 2$

$x = 5 \\y = 2$

6 0

3 years ago

ILL BRAINLIEST YOU IF YOU PLEASE HELP ME

Eddi Din [679]

1 < x < 5

Left side is 1 and right is 5

5 0

3 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

4 years ago

Evaluate the expression when a = 9, b = 2, c = - 6 and d= -4 a-b c-d

Anna35 [415]

Answer:

1. 9-2=7

2. -6-(-4)=-2

Step-by-step explanation:

a=9

b=2

c=-6

d=-4

8 0

1 year ago

What is the surface area of the cone?

goblinko [34]

Answer: C

Step-by-step explanation:

To find the surface area of a cone, you use the formula $A=\pi r(r+\sqrt{h^2+r^2} )$ . Since we are already given the height and radius, all we have to do is plug in the values and solve.

$A=9\pi (9+\sqrt{41^2+9^2} )$ [solve inside of square root]

$A=9\pi (9+\sqrt{1762} )$ [parenthesis]

$A=9\pi (50.976 )$ [multiply]

$A=458$

Therefore, the closest answer is C.

3 0

3 years ago