First we need to find the length of the missing triangle side which we can do with Pythagorean theorem
A2+B2=C2
5^2+3^2= x^2
25+9=x^2
34=x^2
You square booth sides and end up with a decimal of 5.831 rounded for the missing side.
Area for a rectangle is length times width so we multiply 7x5.831=40.817
Area of a triangle is the height times the base divided by 2 so 5.831x3= 17.493
Then you add those to together for the total area of the shape 40.817+17.493=58.31
58.31 is your approximate answer.
Answer:
Step-by-step explanation:
A = L * W
A = 42
W = 3.5
now sub
42 = 3.5L <=== ur equation
<h3>I'll teach you how solve X/3=-19</h3>
-----------------------------------------------
X/3=-19
Multiply both sides by 3:
3x/3= 3(-19)
Simplify:
x= -57
Your Answer Is x= -57
plz mark me as brainliest :)
Answer:
x=43
Step-by-step explanation:
80+65=145
a quadrilateral has 360 degrees
360-145=215 degrees left
3x+2x=5x
5x=215 degrees (divide by 5)
x=42
PLEASE GIVE ME BRAINLIEST!!<3
Answer:
21440
Step-by-step explanation:
<h2>
Simplify:</h2>
Start by multiplying 7x³ by x² and -5.
- 7x⁵ - 35x³ + (8x² - 3)(x² - 5)
Multiply 8x² by x² and -5.
- 7x⁵ - 35x³ + 8x⁴ - 40x² + (-3)(x² - 5)
Multiply -3 by x² and -5.
- 7x⁵ - 35x³ + 8x⁴ - 40x² -3x² + 15
Combine like terms together.
- 7x⁵ - 35x³ + 8x⁴ - 43x² + 15
Rearrange the terms in descending power order.
- 7x⁵ + 8x⁴ - 35x³ - 43x² + 15
<h2>Verify (I): </h2>
Substitute x = 5 into the above polynomial.
- 7(5)⁵ + 8(5)⁴ - 35(5)³ - 43(5)² + 15
Evaluate the exponents first.
- 7(3125) + 8(625) - 35(125) - 43(25) + 15
Multiply the terms together.
- 21875 + 5000 - 4375 - 1075 + 15
Combine the terms together.
This is the answer when substituting x = 5 into the simplified expression.
<h2>
Verify (II):</h2>
Substitute x = 5 into the expression.
- [7(5)³ + 8(5)² - 3][(5)² - 5]
Evaluate the exponents first.
- [7(125) + 8(25) - 3][(25) - 5]
Multiply the terms in the first bracket next.
Evaluate the expressions inside the brackets.
Multiply these two terms together.
This is the answer when substituting x = 5 into the original (unsimplified) expression.