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dedylja [7]
3 years ago
6

Determine the least common multiple (LCM) of 48 and 16.A. 16B. 24C. 36D. 48​

Mathematics
2 answers:
Marizza181 [45]3 years ago
7 0

Answer:

16

since it's the least that can be divided by both

Oxana [17]3 years ago
6 0

Answer:

a) 16

Step-by-step explanation:

Determine the least common multiple (LCM) of 48 and 16.

A. 16

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Answer as soon as possible
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Answer:

-2

-3.1

-2 1/2

Step-by-step explanation:

All are negative and a diver diving into a pool means lower so it is all of the negative ones

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3 years ago
Predict the exam grade for a student who studies 10 hours per week.
user100 [1]

Answer:

100

Step-by-step explanation:

100

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2 years ago
The vertices A(-2,-1), B(-3, 2), C(-1, 3), and D(0, 0) form a parallelogram. The vertices A'(-1, -2), B'(2, -3), C'(3,-1),
attashe74 [19]

Answer:

A is correct.

Step-by-step explanation:

The rule for this transformation is that (x,y) will become (y,x) if it flips over y=x OR the y-axis and the x-axis.

5 0
2 years ago
1. Formulate 500 lbs of a 21% CP ration using Soybean Meal (44% CP) and Corn (9% CP).
zmey [24]

Answer:

Step-by-step explanation:

see sketch below

1 Formulate 500 lbs of a 21% cp ration using soybean meal( 44% cp) and corn (9% cp)

How many pounds of soybean meal will be used?

12 parts soy bean meal/ 35 parts total = 0.34 parts from soy bean meal

0.34 parts from soy bean meal X 500 lbs ration = 170 lbs soy bean meal

How many pounds of corn will be used ?

23 parts corn / 35 parts total = 0.66 parts from corn

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3 0
3 years ago
Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and
ANEK [815]

Answer:

\frac{360000q}{359999}

Step-by-step explanation:

p = Product of all odd integers between 500 an 598. So,

p = 501 x 503 x 505 ... x 595 x 597

q = Product of all odd integers between 500 and 602. So,

q = 501 x 503 x 505 ... x 595 x 597 x 599 x 601

From the above relations, we can see that q is equal to p multiplied by 599 and 601. i.e.

q = p x 599 x 601

or,

p=\frac{q}{599 \times 601}

We need to evaluate 1p + 1q in terms of q. Using the value of p from above expression, we get:

p+q=\frac{q}{599 \times 601} + q\\\\ p+q=\frac{q+(599 \times 601q)}{599 \times 601}\\ \\ p+q=\frac{q(1+599\times601)}{599 \times 601}\\\\ p+q=\frac{360000q}{359999}

7 0
3 years ago
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