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MArishka [77]
3 years ago
13

The average rainfall in inches in Miami from January to May is 1.61, 2.24, 2.99, 3.15, 5.35, and 9.68 while it is 2.24, 2.8, 3.0

3, 2.05, 2.09, and 6.69 during the same period in Tampa.
Which city gets more rain and how much more?

A: Miami gets 0.78 more inches of rain.
B:Tampa gets 5.13 more inches of rain.
C: Miami gets 6.12 more inches of rain.
D: Miami gets 5.35 more inches of rain
Mathematics
2 answers:
vredina [299]3 years ago
6 0
The answer is 100% A
Novosadov [1.4K]3 years ago
4 0

Answer:

I got C

Step-by-step explanation:

( I just did this )

Hope this helps have a nice day :)

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Encuentre el angulo positivo y que es coterminal con -270
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Ok so ummmm idk how to speck in that but well ummmmm idk
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3 years ago
When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of
makkiz [27]

Answer:

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So A(t) \alpha \sin (\frac{t - \alpha }{k} )

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

A(t) = 2.2\sin \frac{(t)}{k} + 0.6

at t = 2 sec volume of a is 0.6

So function reduce to

A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6

and t = 5 max value of volume is represent

so,

\sin \frac{t - \alpha }{k} = 1

\frac{t - 2}{k} = \frac{\pi }{2} when t = 5

\frac{6}{\pi } = k

so the equation becomes

A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6

7 0
3 years ago
I need this answer quick!​
marshall27 [118]

Answer:

Um we can’t see anything it’s just white

Step-by-step explanation:

3 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
Peter has a 25 acre field. He 20.5 acres with sweet corn . What fraction of his field does Peter plant with sweet corn
nata0808 [166]

Answer:

82%

Step-by-step explanation:

Multiply 25*4 to get 100.

Then multiply 20.5*4 because what you do to one side you have to do for the other.

You end up with 0.82 or 82%

5 0
3 years ago
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