Answer:
x = 12
Step-by-step explanation:
1 + 11 = 12, so x = 12. hope this helps
Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
Answer:
Step-by-step explanation:
Answer:
![= { \tt{(0, \: 0)}}](https://tex.z-dn.net/?f=%20%3D%20%7B%20%5Ctt%7B%280%2C%20%5C%3A%200%29%7D%7D)
Step-by-step explanation:
Let:
![{ \bf{ - x - 2y = 0 - - - (a)}} \\ { \bf{y = - 8x - - - (b)}}](https://tex.z-dn.net/?f=%7B%20%5Cbf%7B%20-%20x%20-%202y%20%3D%200%20-%20%20-%20%20-%20%28a%29%7D%7D%20%5C%5C%20%7B%20%5Cbf%7By%20%3D%20%20-%208x%20-%20%20-%20%20-%20%28b%29%7D%7D)
Substitute for y in equation (b) to equation (a):
![{ \tt{ - x - 2( - 8x) = 0}} \\ { \tt{ - x + 16x = 0 }} \\ { \tt{x = 0}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7B%20-%20x%20-%202%28%20-%208x%29%20%3D%200%7D%7D%20%5C%5C%20%7B%20%5Ctt%7B%20-%20x%20%2B%2016x%20%3D%200%20%7D%7D%20%5C%5C%20%7B%20%5Ctt%7Bx%20%3D%200%7D%7D)
Also, y = 0
Answer
x = unidentified
Explanation
If 12÷3=4 and 12 = 4×3, that means 6÷0=x and x×0=6.
This isn't possible because any number divided by 0 is unidentified.