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Doss [256]
2 years ago
9

The table shows the percentage of students in each of three grade levels who list soccer as their favorite sport. Soccer Sophomo

res (35%) 50%
Juniors (33%) 45%
Seniors (32%) 30%
Total (100%) (0.5)(0.35) + (0.45)(0.33) + (0.32)(0.3) = 0.4195 or about 42%
Find the probability that the student is a junior, given that soccer is the favorite sport listed.
P(junior | soccer) = ???%
Mathematics
1 answer:
Olegator [25]2 years ago
4 0
The answer should be roughly 35.4%. 

You can obtain this answer by looking at the percentage of each subgrouping. For instance, 33% of the class in juniors and 45% of them list soccer as their favorites. Thus showing that 14.85% of the entire school is made up of juniors that enjoy soccer. 

If you do the totaling for all soccer lovers, you get a total of 41.95% of the school. By dividing the two numbers you get the answer above. 
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If a number rounded to the nearest tenth is 10.1, which of the following could be the number?
Tatiana [17]
It could be 10.11 10.12 10.13 10.14 
as long as the number next to the one is less than five it will become 10.1
6 0
3 years ago
What is the least common denominator for the fractions 9/14and 2\21
Diano4ka-milaya [45]
Hello : 
14 = 2×7
21 = 3×7
<span> the least common denominator for the fractions 9/14and 2\21  is : 6×7=42</span>
8 0
3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
In an arithmetic sequence, if a2= 5 and a10= 19 find a6
OLEGan [10]

Answer:

a₆ = 12

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂ = 5 and a₁₀ = 19 , then

a₁ + d = 5 → (1)

a₁ + 9d = 19 → (2)

Subtract (1) from (2) term by term to eliminate a₁

8d = 14 ( divide both sides by 8 )

d = 1.75

Substitute d = 1.75 into (1)

a₁ + 1.75 = 5 ( subtract 1.75 from both sides )

a₁ = 3.25

Then

a₆ = 3.25 + 5(1.75) = 3.25 + 8.75 = 12

6 0
2 years ago
___(x – 2)2 − 4 = -3x2 + 12x − 16
fiasKO [112]
The answer is x= 1/5 or 0.2
8 0
3 years ago
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