$98-x^2=0\\\\-x^2+98=0\\\\a=-1\,,\ \ b=0\,,\ \ c=98\\\\x_1=\dfrac{-0-\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{-\sqrt{4\cdot49\cdot2}}{-2}=\dfrac{-2\cdot7\sqrt{2}}{-2}=7\sqrt2\\\\x_2=\dfrac{-0+\sqrt{0^2-4\cdot(-1)\cdot98}}{2\cdot(-1)}=\dfrac{2\cdot7\sqrt{2}}{-2}=-7\sqrt2$

7 0

2 years ago

How do i solve this equation

Gre4nikov [31]

X < -16 is the solution
Hope this helped

6 0

3 years ago

Given h(x) =3x-4 find x if h(x) =17

NikAS [45]

Answer:

x=7

Step-by-step explanation:

h(x) = 17 so you would input 17 for h(x). The equation should look like this. 17= 3x-4. Add 4 to both sides changing the equation to 21 = 3x. Finally divide both side by 3 and you should get x = 7.

6 0

2 years ago

If the function G(x) = (x - 8)2 + 6 has the same shape as F(x) = x2 + 6, how far to the right of F(x) is G(x) shifted?

nikitadnepr [17]

$G(x) = (x - 8)^2 + 6\ \ \ and\ \ \ F(x) = x^2 + 6\\\\Ans.\ G(x)\ is\ shifted\ 8\ units\ right\ to\ the\ F(x)$

8 0

3 years ago