First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62
now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407
Hello from MrBillDoesMath!
Answer:
x < -2
Discussion:
7 < 3 - 2x => Add 2x to both sides
7 + 2x < 3 - (2x - 2x) => As 2x -2x = 0
7 + 2x < 3 => Subtract 7 from both sides
(7-7) + 2x < 3 - 7 => As 7-7 = 0 and 3-7 = -4
2x < -4 => Divide both sides by 2
x < -4./2 = -2
Thank you,
MrB
Step-by-step explanation:
-x+2y=-6
x-2y=6
x=2y+6
substitute in 2x-3y=11 gives us 2(2y+6)-3y=11
4y+12-3y=11
y=-1
-x+2(-1)=-6
-x=-4
x=4
Answer:
6
Step-by-step explanation:
This is a plain and simple answer. No distributive property here!
68 ÷ 4 = 17
