Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Step-by-step explanation:
Given ,
Current balance $320
Minimum balance $100
I could spent =$(320-100) = $220
Let the number of bills be x.
Total amount of x bills = $20x
According to the problem,
20x≤ 220
⇔x ≤ 
⇔x≤11
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Answer:
steps 3 went wrong
Step-by-step explanation:
the quadratic is
(-b +/- √ ( b^2 - 4ac) )/2a
-52 + √( 2704 +2772) /-14
-52 +74) / -14 = -22/14 = -11/7
-52 -74 / -14 = -126/-14 = 9
Answer:
Hope you will understand my handwriting and hope it helps.