Question

Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndRoot Over 2 (10) EndFraction for x?
10x2 = 3x + 2
2 = 3x + 10x2
3x = 10x2 – 2
10x2 + 2 = –3x

Answer 1

Answer:

2 = 3x + 10x^2

Step-by-step explanation:

There for the answer is B

Answer 2

Answer: B.  2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt(3^2+4(10)(2))]/(2(10))

The formual that was applied here was a quadratic formula given by:

x=[-b+\-sqrt(b^2-4ac)]/2a

whereby from the our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2