Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR
2 answers:
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Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that ,
and
, then the coordinates of the image of the original point is:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Answer:
28.26
Step-by-step explanation:
The radius is half of the diameter. 6/2 = 3, so the radius of this circle is 3 cm.
The formula for the area of a circle is: π
Plugging 3 into the radius, we have:
× π =
9 × π
We can round π to 3.14
9 × 3.14 = 28.26