Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR oot Over 2 (10) EndFraction for x? 10x2 = 3x + 2
2 = 3x + 10x2
3x = 10x2 – 2
10x2 + 2 = –3x
2 answers:
Answer:
2 = 3x + 10x^2
Step-by-step explanation:
There for the answer is B
Answer: B. 2 = 3x + 10x2
Step-by-step explanation:
This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:
[-3+-sqrt(3^2+4(10)(2))]/(2(10))
The formual that was applied here was a quadratic formula given by:
x=[-b+\-sqrt(b^2-4ac)]/2a
whereby from the our substituted values above,
a=10,b=3 and c=-2
such that the quadratic equation will be:
10x^2+3x-2
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