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kifflom [539]
2 years ago
5

Find the area of the shape shown below... please

Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0

Answer:

12.5

Step-by-step explanation:

You would solve by taking A=1/2(7.5+2.5)*2.5=12.5

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Explain your answer !!<br><br> Will give brainlst
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Answer:

(-2, 2)

Step-by-step explanation:

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Step-by-step explanation:

6^2+h^2=10^2

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3 years ago
Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

<em><u>Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars</u></em>

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

14c + 5v = 119 ------- eqn 1

<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

10c + 10v = 130 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
Please help me with this question
Y_Kistochka [10]

Answer:

2(a - 4) + 5(b + 1) = 8. The result of this equation when solving is a = - 5b/2 + 11/2.

3(a - 1) - 2(b - 2) = -11. The result of this equation when solving is a = 2b/3 - 4.

Step-by-step explanation:

Hope this helps =)

8 0
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