Answer:
= 10
Step-by-step explanation:
w + 9
if, w = 1
SO...
1 + 9 = 10
7 yrds/sec because in the course of two seconds, he runs 14 yrds divide that by 2 to get 7 yrds/sec. you can allo chech with the next time which is 3 seconds more and he goes 21 yards more.
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
Answer:
x = 5
Step-by-step explanation:
sin theta = opposite side / hypotenuse
sin 53 = 4/x
Multiply each side by x
x sin 53 = 4/x *x
x sin 53 = 4
Divide each side by sin 53
x sin 53 / sin 53 = 4 / sin 53
x = 4 /sin 53
x = 5.008542633
To the nearest whole number
x = 5
