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3 years ago

Can someone help me slove this ?

Mathematics

2 answers:

Veronika [31]3 years ago

6 0

Answer:

x<-1

Step-by-step explanation:

I think and hope it helps

suter [353]3 years ago

3 0

Answer:

remember me

Step-by-step explanation:

You might be interested in

Worker A can finish a job in

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

$\frac{1}{2} - \frac{1}{3} \\ \\ = \frac{1}{6} \times 24 \\ = 4$

8 0

3 years ago

What is the length of the hypotenuse? 24 42

AleksAgata [21]

Answer:

The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem or a^2+b^2=c^2.

(24)^2+(42)^2=2340

Step-by-step explanation:

Are the 24 and 42 squared already or no just let me know if they are squared then I'll change my answer okay

7 0

3 years ago

Read 2 more answers

Please help me with number 1 to 6 please

Ugo [173]

1.) 144
2.) 8
3.) 262.5
4.) 36
5.) 630
6.) 440

8 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

4 years ago

Write a numerical expression for 6 times the sum of 3 and 7

kompoz [17]

Answer:

6(3+7)

Step-by-step explanation:

i believe that is correct

6 0

3 years ago