False, that is an external stimulus
Answer:
One of the RNA molecules has experienced gene duplication as the result of translocation.
Explanation:
Translocation and duplication are some of the structural abnormalities in the chromosomes that may even cause certain genetic disorders. Duplication is the presence of a genetic segment for more than one time in the chromosome. The repeated genetic segments are mostly present in the tandem pattern. When a chromosome fragment breaks off and attaches to a non-homologous chromosome, it is called translocation. It leads to the deletion of a genetic segment in one chromosome and duplication in the other.
According to the given information, a genetic segment bearing two genes is detached from one RNA and gets attached to the other RNA molecule of the HIV genome. Therefore, the RNA molecule has undergone translocation and has lost a genetic segment while the other has gained a genetic segment (duplication) due to translocation.
Answer:
COOH (carboxyl group)
Explanation:
The amino acid backbone is common/ primary to all amino acids and the R-group is what makes each amino acid unique. The alpha-carbon is central and is connected to the amino group (NH3+), Carboxylic acid group (COOH), Hydrogen (H) which form the backbone and the R-group which differs in each amino acid.
Answer:
one half or one fourth or three fourths
Explanation:
just depends
Answer:
See the answer with the explanation below.
Explanation:
Assuming the allele for sickle cell disease is represented by S and the alternate, non-sickle cell version is A; AA would be <em>homozygous normal</em>, AS would be <em>heterozygous normal</em>, and SS would be a <em>sickler</em>.
a. <em>The genotype of the father in the first generation would be </em><em>AS</em>.
The father is heterozygous, since the mother is affected and the couple produced an affected child. The cross can be illustrated thus:
AS (father) x SS (mother) = AS, AS, SS, SS
b. <em>The genotype of the daughter in the second generation would be </em><em>SS</em><em> </em>since she is phenotypically affected for the disease.
c. <em>The genotype of individual 3 in the second generation would be heterozygous, </em><em>AS</em>.
The cross between the the heterozygous normal father and the sickler mother can only produce one of heterozygous normal individuals or sickle cell diseased individuals. Hence, individual 3 has to be heterozygous since he appeared phenotypically normal in the pedigree.