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Ganezh [65]
3 years ago
13

HELP ME PLEASE!!!!!!!!

Mathematics
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

10

Step-by-step explanation:

(4 * 5) / 2 = 20 / 2 = 10

Black_prince [1.1K]3 years ago
3 0

Answer:

Triangle R and triangle S are congruent triangles, so finding the area of triangle S would give us the area  of triangle R.

The area of  a triangle can be calculated as 1/2(bh), where b is the base and h is the height.

In this case, we have: 1/2(5)(4). This simplifies to 10.

So, the area of triangle R is 10 square meters.

Let me know if this helps!

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A student draws the net below to show the dimensions of the container that is shaped like a right rectangular prism. What is the
ZanzabumX [31]

Answer:

The correct option is;

D) 62 in²

Step-by-step explanation:

Here we have from the drawing, the dimensions of the right rectangular prism are;

Height = 2 in.

Width = 5 in

Length = 3 in

Therefore the surface area is found as follows;

Surface area of right rectangular prism = 2 × Height × Width + 2 × Height × Length + 2  × Width × Length

Surface area of right rectangular prism = 2 × 2 × 5 + 2 × 2× 3+ 2  × 5× 3 = 20 + 12 + 30 = 62 in².

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3 years ago
From a survey of 60 students attending a university, it was found that 9 were living off campus, 36 were undergraduates, and 3 w
lana66690 [7]
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.

6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
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Therefore, there are 18 students who are neither an undergraduate nor living off-campus

8 0
3 years ago
What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
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Natalija [7]

Answer:

C:  Point R

Step-by-step explanation:

Here the "centroid" corresponds to the point where the figure (the triangle) would balance.  That's right in the middle, at Point R.  C is the correct answer.

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Answer:

Step-by-step explanation:

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3 years ago
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