Answer:
1. Because a right angle is 90 degrees, the answer to this is 90 - 65 = 25.
2. This question is similar to the last one, but this time the angle is 180 degrees total, so the answer is 180 - 55 = 125.
3. I'm fairly certain the lines here indicate that all three angles are the same. If all three angles make 180 degrees, the answer would be 180 / 3 = 60.
4. This is the same as in question 2. 180 - 135 = 45.
5. Again, because all three angles need to make up 180 degrees, we can just simply do 180 - (65 + 45) = 70.
6. With a quadrilateral, the angles add up to 360 degrees. We can do the same thing as in question 5 here. 360 - (70 + 95 + 55) = 140.
7. I don't remember exactly how to solve this but 55 degrees is correct because 55 + 55 + 70 = 180 which is the only possible value.
I haven't done this kind of stuff in a looooong time so I hope this suffices! :)
Answer:
5x^2 -3x +9
Step-by-step explanation:
To subtract, line up the common terms. I add a 0 term to keep the terms in line.
5x^2 + 0x +7
- (0x^2 +3x- 2 )
------------------------
Distribute the negative sign.
5x^2 + 0x +7
- 0x^2 -3x + 2
------------------------
5x^2 -3x +9
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) 
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) 
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
Answer:c
15x - 4
Step-by-step explanation:
15x - 4
